디지털 工學(공학) BCD adder & Encoder
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작성일 23-05-22 04:40
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Download : 디지털 공학 BCD adder Enc.hwp
Etc·································································006
So, 이를 회로로 표현 하자면
ㄷ. 일 때 이므로
BCD 는 십진수의 한 자리를 4bit로 표현을 한다.
레포트 > 공학,기술계열
디지털 공학 ,BCD adder. Encoder
2) Priority Encoder
Download : 디지털 공학 BCD adder Enc.hwp( 76 )
이 값에 영향을 주지 않는 input W를 추가하여
chapter4
① 4bit Adder를 통하여 두 수를 덧셈을 해준다. So, 이를 회로도로 표현 하자면
Contents····························································003
Simulation···························································006
② 만약 이 수가 10~19까지의 수이라면 이 숫자를 다시 한 번 4bit adder를 통해 6을 더해 준다.
설명
Encoder에서의 Input과 Output의 관계는 이다.
순서
Logic gate···························································005
chapter5
hapter1 Contents····························································003 chapter2 Logic gate···························································005 chapter3 Simulation···························································006 chapter4 Picture······························································006 chapter5 Etc·································································006
①②③④⑤⑥⑦⑧⑨⑩
디지털 工學(공학) BCD adder & Encoder
그렇다면 어떻게 10진수처럼 보이게 만드는 방법은 A(10)~F(15)까지의 수에만 6을 더하면 십진수처럼 보이게 된다된다.
hapter1
ㄴ. 일 때
Picture······························································006
일 때 Carry가 발생하게 될 것이고 또 한 이때에 두 번째 4bit Adder에서 6을 덧셈을 해주면 된다된다.
※설계 순서
chapter2
③ 이 수가 10~19임을 알 수확인 하는 방법은 ㄱ. 첫 번째 4bit Adder에서 Carry가 발생 하였을 때와 즉 K 일 때
chapter3
하지만 7-segment에 들어가려면 4개의 input이 있어야 한다. 고로 버튼의 스위치의 갯수는 6가지이므로 이고 이 된다된다. 하지만 저번 실험에서 했던 4bit-Adder의 7-Segment 출력의 결과는 16진수의 표현 이였다.
다.
